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feat: theorems for ushiftRight #33

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45 changes: 45 additions & 0 deletions src/Init/Data/BitVec/Lemmas.lean
Original file line number Diff line number Diff line change
Expand Up @@ -1316,6 +1316,51 @@ theorem toNat_ushiftRight_lt (x : BitVec w) (n : Nat) (hn : n ≤ w) :
· apply hn
· apply Nat.pow_pos (by decide)


/-- Shifting right by `n`, which is larger than the bitwidth `w` produces `0. -/
theorem ushiftRight_eq_zero {x : BitVec w} {n : Nat} (hn : w ≤ n) :
x >>> n = 0#w := by
simp [bv_toNat]
have : 2^w ≤ 2^n := Nat.pow_le_pow_of_le Nat.one_lt_two hn
rw [Nat.shiftRight_eq_div_pow, Nat.div_eq_of_lt (by omega)]


/--
Unsigned shift right by at least one bit makes the value of the bitvector less than or equal to `2^(w-1)`,
makes the interpretation of the bitvector `Int` and `Nat` agree.

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makes the two times in a row is grammatically suspicious.

-/
theorem toInt_ushiftRight_of_lt {x : BitVec w} {n : Nat} (hn : 0 < n) :
(x >>> n).toInt = x.toNat >>> n := by
rw [toInt_eq_toNat_cond]
simp only [toNat_ushiftRight, ite_eq_left_iff, Nat.not_lt]
intros h
by_cases hn: n ≤ w
· have h1 := Nat.mul_lt_mul_of_pos_left (toNat_ushiftRight_lt x n hn) Nat.two_pos
simp only [toNat_ushiftRight, Nat.zero_lt_succ, Nat.mul_lt_mul_left] at h1
have : 2 ^ (w - n).succ ≤ 2^ w := Nat.pow_le_pow_of_le (by decide) (by omega)
have := show 2 * x.toNat >>> n < 2 ^ w by
omega
omega
· have : x.toNat >>> n = 0 := by

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Can this be simplified with ushiftRight_eq_zero?

apply Nat.shiftRight_eq_zero
have : 2^w ≤ 2^n := Nat.pow_le_pow_of_le (by decide) (by omega)
omega
simp [this] at h
omega

/--
Unsigned shift right by at least one bit makes the value of the bitvector less than or equal to `2^(w-1)`,
makes the interpretation of the bitvector `Int` and `Nat` agree.
In the case when `n = 0`, then the shift right value equals the integer interpretation.
-/
@[simp]
theorem toInt_ushiftRight_eq_ite {x : BitVec w} {n : Nat} :
(x >>> n).toInt = if n = 0 then x.toInt else x.toNat >>> n := by
by_cases hn : n = 0
· simp [hn]
· rw [toInt_ushiftRight_of_lt (by omega), toInt_eq_toNat_cond]
simp [hn]

@[simp]
theorem getMsbD_ushiftRight {x : BitVec w} {i n : Nat} :
(x >>> n).getMsbD i = (decide (i < w) && (!decide (i < n) && x.getMsbD (i - n))) := by
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4 changes: 4 additions & 0 deletions src/Init/Data/Int/Bitwise/Lemmas.lean
Original file line number Diff line number Diff line change
Expand Up @@ -34,4 +34,8 @@ theorem shiftRight_eq_div_pow (m : Int) (n : Nat) :
theorem zero_shiftRight (n : Nat) : (0 : Int) >>> n = 0 := by
simp [Int.shiftRight_eq_div_pow]

@[simp]
theorem shiftRight_zero (n : Int) : n >>> 0 = n := by
simp [Int.shiftRight_eq_div_pow]
Comment on lines +38 to +39

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Should n be of type BitVec?


end Int
3 changes: 3 additions & 0 deletions src/Init/Data/Nat/Bitwise/Basic.lean
Original file line number Diff line number Diff line change
Expand Up @@ -71,6 +71,9 @@ theorem shiftRight_eq_div_pow (m : Nat) : ∀ n, m >>> n = m / 2 ^ n
rw [shiftRight_add, shiftRight_eq_div_pow m k]
simp [Nat.div_div_eq_div_mul, ← Nat.pow_succ, shiftRight_succ]

theorem shiftRight_eq_zero (m n : Nat) (hn : m < 2^n) : m >>> n = 0 := by
simp [Nat.shiftRight_eq_div_pow, Nat.div_eq_of_lt hn]

/-!
### testBit
We define an operation for testing individual bits in the binary representation
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